Not sure if this made it,...resending...

--------------------------
Thanks for the replies.  

I've been trying to learn the Cybil syntax and thought I
had it until I saw the "p2" below.  Can anyone point out
the flaw in my logic?  

On Sun, 15 Jun 1997, Jean Piche wrote:

> instr 4
> p2 {sq 1 {sq {sq 0 6}  4 3} {sq 0 6} 14s} ;

To me, this means:

   p2  {  sq  1  {sq 000000 4 3}  {0 0 0 0 0 0}  14s}

which means
 
   p2  {  sq  1  000000400000040000004 000000 14s}

which doesn't look like the pattern below...

Is my understanding of p2 above correct?
--------------------
i4 1
i4 1
i4 1
i4 1
i4 1
i4 1
i4 5
i4 5