| Not sure if this made it,...resending...
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Thanks for the replies.
I've been trying to learn the Cybil syntax and thought I
had it until I saw the "p2" below. Can anyone point out
the flaw in my logic?
On Sun, 15 Jun 1997, Jean Piche wrote:
> instr 4
> p2 {sq 1 {sq {sq 0 6} 4 3} {sq 0 6} 14s} ;
To me, this means:
p2 { sq 1 {sq 000000 4 3} {0 0 0 0 0 0} 14s}
which means
p2 { sq 1 000000400000040000004 000000 14s}
which doesn't look like the pattern below...
Is my understanding of p2 above correct?
--------------------
i4 1
i4 1
i4 1
i4 1
i4 1
i4 1
i4 5
i4 5 |