i()

i()

Date	2015-11-08 16:25
From	christos
Subject	i()
	hello all i need to convert a k-rate argument to an i-statement using i(). the k-rate data is coming via a zak patch from instr 1 to an instrument that is triggered by schedkwhen (instr 2). the k-rate signal is not 0, i have checked this using printk in instr 2. however, and only when i use it in a comb filter i get a value of 0 (see a simplified flow below). other uses such as in oscil or reson etc work fine. instr 2; comb filter on L channel aL zar 1 kcpsL zkr 1 ; /not zero - have checked/ krmsrL zkr 3 ifr = i(kcpsL) print ifr; /this returns a value of zero on the init pass when the instr is triggered bit only when leading to comb./ acL comb aL, 10, 1/ifr outs acL, acL endin any ideas what i might be doing wrong or has this something to do with the internal workings of comb? many thanks christos -- View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946.html Sent from the Csound - General mailing list archive at Nabble.com. Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 16:51
From	jpff
Subject	Re: i()
	more to do with the internal wiorkings of csound. The assignment to ifr happens at init time while the zar runs at kperf time. i() cannot reverse time On Sun, 8 Nov 2015, christos wrote: > hello all > > i need to convert a k-rate argument to an i-statement using i(). the k-rate > data is coming via a zak patch from instr 1 to an instrument that is > triggered by schedkwhen (instr 2). the k-rate signal is not 0, i have > checked this using printk in instr 2. > > however, and only when i use it in a comb filter i get a value of 0 (see a > simplified flow below). other uses such as in oscil or reson etc work fine. > > instr 2; comb filter on L channel > > aL zar 1 > kcpsL zkr 1 ; /not zero - have checked/ > krmsrL zkr 3 > > ifr = i(kcpsL) > > print ifr; /this returns a value of zero on the init pass > when the instr is triggered bit only when leading to comb./ > > acL comb aL, 10, 1/ifr > > outs acL, acL > > endin > > any ideas what i might be doing wrong or has this something to do with the > internal workings of comb? > > many thanks > > christos > > > > -- > View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946.html > Sent from the Csound - General mailing list archive at Nabble.com. > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here > Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 18:50
From	Anders Genell
Subject	Re: i()
	For such situations, could one use reinit to make the conversion happen after a first k-cycle? Regards, Anders > 8 nov. 2015 kl. 17:51 skrev jpff : > > more to do with the internal wiorkings of csound. The assignment to ifr happens at init time while the zar runs at kperf time. i() cannot reverse time > >> On Sun, 8 Nov 2015, christos wrote: >> >> hello all >> >> i need to convert a k-rate argument to an i-statement using i(). the k-rate >> data is coming via a zak patch from instr 1 to an instrument that is >> triggered by schedkwhen (instr 2). the k-rate signal is not 0, i have >> checked this using printk in instr 2. >> >> however, and only when i use it in a comb filter i get a value of 0 (see a >> simplified flow below). other uses such as in oscil or reson etc work fine. >> >> instr 2; comb filter on L channel >> >> aL zar 1 >> kcpsL zkr 1 ; /not zero - have checked/ >> krmsrL zkr 3 >> >> ifr = i(kcpsL) >> >> print ifr; /this returns a value of zero on the init pass >> when the instr is triggered bit only when leading to comb./ >> >> acL comb aL, 10, 1/ifr >> >> outs acL, acL >> >> endin >> >> any ideas what i might be doing wrong or has this something to do with the >> internal workings of comb? >> >> many thanks >> >> christos >> >> >> >> -- >> View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946.html >> Sent from the Csound - General mailing list archive at Nabble.com. >> >> Csound mailing list >> Csound@listserv.heanet.ie >> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >> Send bugs reports to >> https://github.com/csound/csound/issues >> Discussions of bugs and features can be posted here > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 21:39
From	christos
Subject	Re: i()
	thank you both for your input. but i still don't understand why the procedure works with reson and not with comb.... christos -- View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744950.html Sent from the Csound - General mailing list archive at Nabble.com. Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 21:58
From	Victor Lazzarini
Subject	Re: i()
	Can you show us the comb instrument that works? Then we can explain. ======================== Dr Victor Lazzarini Dean of Arts, Celtic Studies and Philosophy, Maynooth University, Maynooth, Co Kildare, Ireland Tel: 00 353 7086936 Fax: 00 353 1 7086952 > On 8 Nov 2015, at 21:39, christos wrote: > > thank you both for your input. but i still don't understand why the procedure > works with reson and not with comb.... > > christos > > > > -- > View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744950.html > Sent from the Csound - General mailing list archive at Nabble.com. > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 22:22
From	christos
Subject	Re: i()
	sure (but comb doesn't work, reson does, as in the orc below. if is use comb instead of reson it doesn't work), thanks a lot! : sr = 44100 ksmps = 128 nchnls = 2 0dbfs = 1.0 zakinit 5, 5 instr 1; ktime timeinsts outvalue "ktime", ktime aL, aR soundin "level5.wav" ktim line 0, p3, 120 kgain1 ctrl7 1, 0, 0, 1 kgain1 portk kgain1, 0.1 outvalue "kgain1", kgain1 krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL if (krmsrL > 1) then ktrigL = 1 elseif (krmsrL <1) then ktrigL = 0 endif if (krmsrR > 1) then ktrigR = 1 elseif (krmsrR <1) then ktrigR = 0 endif schedkwhen ktrigL, 0, 15, 2, 0, 13 schedkwhen ktrigR, 0, 15, 3, 0, 13 outs aLkgain1, aRkgain1 zaw aL, 1 zaw aR, 2 zkw kcpsL, 1 zkw kcpsR, 2 zkw krmsrL, 3 zkw krmsrR, 4 endin instr 2; reson filter on L channel seed 0 irand random 7, 12.9 kcpsL zkr 1 ifr = i(kcpsL) print ifr aL zar 1 krmsrL zkr 3 kgain2 ctrl7 1, 1, 0, 1 kgain2 portk kgain2, 0.1 outvalue "kgain2", kgain2 aL = aLkgain2 kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 acL butterhp acL, 70 acL reson acL, ifr, ifr/10 acL balance acL, aL acL = acLkenv apL, apR pan2 acL, krmsrL/1.6 outs apL, apR endin instr 3; reson filter on R channel seed 0 irand random 6, 12.9 kcpsR zkr 2 ifr = i(kcpsR) print ifr aR zar 2 krmsrR zkr 4 kgain3 ctrl7 1, 2, 0, 1 kgain3 portk kgain3, 0.1 outvalue "kgain3", kgain3 aR = aRkgain3 kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 acR butterhp acR, 70 acR reson aR, ifr, ifr/10 acR balance acR, aR acR = acRkenv apL, apR pan2 acR, 1-(krmsrR/1.6) outs apL, apR endin f1 0 16384 10 1 i 1 0 140 i 2 0 140 i 3 0 140 e ----- Christos Carras -- View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html Sent from the Csound - General mailing list archive at Nabble.com. Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-08 22:51
From	Victor Lazzarini
Subject	Re: i()
	I am not sure what you mean in terms of “working”. The value for ifr is going to be 0 whether you use comb or reson. Except that reson will not give you an init error for that. The reason for 0 has already been explained here. It is the value of kcpsL at i-time the first time you run the instrument. You will see that print ifr prints 0. ======================== Dr Victor Lazzarini Dean of Arts, Celtic Studies and Philosophy, Maynooth University, Maynooth, Co Kildare, Ireland Tel: 00 353 7086936 Fax: 00 353 1 7086952 > On 8 Nov 2015, at 22:22, christos wrote: > > sure (but comb doesn't work, reson does, as in the orc below. if is use comb > instead of reson it doesn't work), thanks a lot! : > > > > > > > sr = 44100 > ksmps = 128 > nchnls = 2 > 0dbfs = 1.0 > > zakinit 5, 5 > > > instr 1; > > ktime timeinsts > outvalue "ktime", ktime > > aL, aR soundin "level5.wav" > > ktim line 0, p3, 120 > > kgain1 ctrl7 1, 0, 0, 1 > kgain1 portk kgain1, 0.1 > outvalue "kgain1", kgain1 > > krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" > krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" > > ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL > > if (krmsrL > 1) then > ktrigL = 1 > elseif (krmsrL <1) then > ktrigL = 0 > endif > > if (krmsrR > 1) then > ktrigR = 1 > elseif (krmsrR <1) then > ktrigR = 0 > endif > > schedkwhen ktrigL, 0, 15, 2, 0, 13 > schedkwhen ktrigR, 0, 15, 3, 0, 13 > > outs aLkgain1, aRkgain1 > > zaw aL, 1 > zaw aR, 2 > zkw kcpsL, 1 > zkw kcpsR, 2 > zkw krmsrL, 3 > zkw krmsrR, 4 > > endin > > instr 2; reson filter on L channel > > seed 0 > > irand random 7, 12.9 > > kcpsL zkr 1 > ifr = i(kcpsL) > print ifr > > aL zar 1 > krmsrL zkr 3 > > kgain2 ctrl7 1, 1, 0, 1 > kgain2 portk kgain2, 0.1 > outvalue "kgain2", kgain2 > > aL = aLkgain2 > > kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 > > acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 > acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 > acL butterhp acL, 70 > acL reson acL, ifr, ifr/10 > acL balance acL, aL > > acL = acLkenv > > apL, apR pan2 acL, krmsrL/1.6 > > outs apL, apR > > endin > > instr 3; reson filter on R channel > > seed 0 > > irand random 6, 12.9 > > kcpsR zkr 2 > ifr = i(kcpsR) > print ifr > > aR zar 2 > krmsrR zkr 4 > > kgain3 ctrl7 1, 2, 0, 1 > kgain3 portk kgain3, 0.1 > outvalue "kgain3", kgain3 > > aR = aRkgain3 > > kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 > > acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 > acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 > acR butterhp acR, 70 > acR reson aR, ifr, ifr/10 > acR balance acR, aR > > acR = acRkenv > > apL, apR pan2 acR, 1-(krmsrR/1.6) > > outs apL, apR > > endin > > > > > > f1 0 16384 10 1 > > i 1 0 140 > i 2 0 140 > i 3 0 140 > > e > > > > > > > ----- > Christos Carras > -- > View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html > Sent from the Csound - General mailing list archive at Nabble.com. > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-09 07:48
From	Oeyvind Brandtsegg
Subject	Re: i()
	As Victor and John says the value will be zero the first time (if you run instr 2 and 3 at time zero). But if you delay the start of instr 2 and 3 until instr 1 have run a few cycles (and writing something to the zak channel), then it should work. I haven't tried to run the code, but wonder why you start instr 2 and 3 from the score and trigger them via schedkwhen? It seems perhaps only the schedkwhen triggering is what you want? Also, it is generally recommended to use chn channels in place of zak. (zak being an intermediate workaround born at a time when chn channels and arrays was not implemented in Csound yet). best Oeyvind 2015-11-08 23:51 GMT+01:00 Victor Lazzarini : > I am not sure what you mean in terms of “working”. The value for ifr is going to be 0 whether you > use comb or reson. Except that reson will not give you an init error for that. > > The reason for 0 has already been explained here. It is the value of kcpsL at i-time the first time you > run the instrument. You will see that print ifr prints 0. > > ======================== > Dr Victor Lazzarini > Dean of Arts, Celtic Studies and Philosophy, > Maynooth University, > Maynooth, Co Kildare, Ireland > Tel: 00 353 7086936 > Fax: 00 353 1 7086952 > >> On 8 Nov 2015, at 22:22, christos wrote: >> >> sure (but comb doesn't work, reson does, as in the orc below. if is use comb >> instead of reson it doesn't work), thanks a lot! : >> >> >> >> >> >> >> sr = 44100 >> ksmps = 128 >> nchnls = 2 >> 0dbfs = 1.0 >> >> zakinit 5, 5 >> >> >> instr 1; >> >> ktime timeinsts >> outvalue "ktime", ktime >> >> aL, aR soundin "level5.wav" >> >> ktim line 0, p3, 120 >> >> kgain1 ctrl7 1, 0, 0, 1 >> kgain1 portk kgain1, 0.1 >> outvalue "kgain1", kgain1 >> >> krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" >> krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" >> >> ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL >> >> if (krmsrL > 1) then >> ktrigL = 1 >> elseif (krmsrL <1) then >> ktrigL = 0 >> endif >> >> if (krmsrR > 1) then >> ktrigR = 1 >> elseif (krmsrR <1) then >> ktrigR = 0 >> endif >> >> schedkwhen ktrigL, 0, 15, 2, 0, 13 >> schedkwhen ktrigR, 0, 15, 3, 0, 13 >> >> outs aLkgain1, aRkgain1 >> >> zaw aL, 1 >> zaw aR, 2 >> zkw kcpsL, 1 >> zkw kcpsR, 2 >> zkw krmsrL, 3 >> zkw krmsrR, 4 >> >> endin >> >> instr 2; reson filter on L channel >> >> seed 0 >> >> irand random 7, 12.9 >> >> kcpsL zkr 1 >> ifr = i(kcpsL) >> print ifr >> >> aL zar 1 >> krmsrL zkr 3 >> >> kgain2 ctrl7 1, 1, 0, 1 >> kgain2 portk kgain2, 0.1 >> outvalue "kgain2", kgain2 >> >> aL = aLkgain2 >> >> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >> >> acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 >> acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 >> acL butterhp acL, 70 >> acL reson acL, ifr, ifr/10 >> acL balance acL, aL >> >> acL = acLkenv >> >> apL, apR pan2 acL, krmsrL/1.6 >> >> outs apL, apR >> >> endin >> >> instr 3; reson filter on R channel >> >> seed 0 >> >> irand random 6, 12.9 >> >> kcpsR zkr 2 >> ifr = i(kcpsR) >> print ifr >> >> aR zar 2 >> krmsrR zkr 4 >> >> kgain3 ctrl7 1, 2, 0, 1 >> kgain3 portk kgain3, 0.1 >> outvalue "kgain3", kgain3 >> >> aR = aRkgain3 >> >> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >> >> acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 >> acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 >> acR butterhp acR, 70 >> acR reson aR, ifr, ifr/10 >> acR balance acR, aR >> >> acR = acRkenv >> >> apL, apR pan2 acR, 1-(krmsrR/1.6) >> >> outs apL, apR >> >> endin >> >> >> >> >> >> f1 0 16384 10 1 >> >> i 1 0 140 >> i 2 0 140 >> i 3 0 140 >> >> e >> >> >> >> >> >> >> ----- >> Christos Carras >> -- >> View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html >> Sent from the Csound - General mailing list archive at Nabble.com. >> >> Csound mailing list >> Csound@listserv.heanet.ie >> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >> Send bugs reports to >> https://github.com/csound/csound/issues >> Discussions of bugs and features can be posted here > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here -- Oeyvind Brandtsegg Professor of Music Technology NTNU 7491 Trondheim Norway Cell: +47 92 203 205 http://flyndresang.no/ http://www.partikkelaudio.com/ http://soundcloud.com/brandtsegg http://soundcloud.com/t-emp Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-09 09:21
From	Victor Lazzarini
Subject	Re: i()
	I am not sure that zak would write to the variable at i-time (it shouldn’t, but it might do). In this case, the k-variable will be 0 until perf time. If the same instance of instrs 2/3 is reused, then at i-time the k-variable will have whatever value it held at the final k-cycle in the previous performance. ======================== Dr Victor Lazzarini Dean of Arts, Celtic Studies and Philosophy, Maynooth University, Maynooth, Co Kildare, Ireland Tel: 00 353 7086936 Fax: 00 353 1 7086952 > On 9 Nov 2015, at 07:48, Oeyvind Brandtsegg wrote: > > As Victor and John says the value will be zero the first time (if you > run instr 2 and 3 at time zero). But if you delay the start of instr 2 > and 3 until instr 1 have run a few cycles (and writing something to > the zak channel), then it should work. > I haven't tried to run the code, but wonder why you start instr 2 and > 3 from the score and trigger them via schedkwhen? It seems perhaps > only the schedkwhen triggering is what you want? Also, it is generally > recommended to use chn channels in place of zak. (zak being an > intermediate workaround born at a time when chn channels and arrays > was not implemented in Csound yet). > > best > Oeyvind > > 2015-11-08 23:51 GMT+01:00 Victor Lazzarini : >> I am not sure what you mean in terms of “working”. The value for ifr is going to be 0 whether you >> use comb or reson. Except that reson will not give you an init error for that. >> >> The reason for 0 has already been explained here. It is the value of kcpsL at i-time the first time you >> run the instrument. You will see that print ifr prints 0. >> >> ======================== >> Dr Victor Lazzarini >> Dean of Arts, Celtic Studies and Philosophy, >> Maynooth University, >> Maynooth, Co Kildare, Ireland >> Tel: 00 353 7086936 >> Fax: 00 353 1 7086952 >> >>> On 8 Nov 2015, at 22:22, christos wrote: >>> >>> sure (but comb doesn't work, reson does, as in the orc below. if is use comb >>> instead of reson it doesn't work), thanks a lot! : >>> >>> >>> >>> >>> >>> >>> sr = 44100 >>> ksmps = 128 >>> nchnls = 2 >>> 0dbfs = 1.0 >>> >>> zakinit 5, 5 >>> >>> >>> instr 1; >>> >>> ktime timeinsts >>> outvalue "ktime", ktime >>> >>> aL, aR soundin "level5.wav" >>> >>> ktim line 0, p3, 120 >>> >>> kgain1 ctrl7 1, 0, 0, 1 >>> kgain1 portk kgain1, 0.1 >>> outvalue "kgain1", kgain1 >>> >>> krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" >>> krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" >>> >>> ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL >>> >>> if (krmsrL > 1) then >>> ktrigL = 1 >>> elseif (krmsrL <1) then >>> ktrigL = 0 >>> endif >>> >>> if (krmsrR > 1) then >>> ktrigR = 1 >>> elseif (krmsrR <1) then >>> ktrigR = 0 >>> endif >>> >>> schedkwhen ktrigL, 0, 15, 2, 0, 13 >>> schedkwhen ktrigR, 0, 15, 3, 0, 13 >>> >>> outs aLkgain1, aRkgain1 >>> >>> zaw aL, 1 >>> zaw aR, 2 >>> zkw kcpsL, 1 >>> zkw kcpsR, 2 >>> zkw krmsrL, 3 >>> zkw krmsrR, 4 >>> >>> endin >>> >>> instr 2; reson filter on L channel >>> >>> seed 0 >>> >>> irand random 7, 12.9 >>> >>> kcpsL zkr 1 >>> ifr = i(kcpsL) >>> print ifr >>> >>> aL zar 1 >>> krmsrL zkr 3 >>> >>> kgain2 ctrl7 1, 1, 0, 1 >>> kgain2 portk kgain2, 0.1 >>> outvalue "kgain2", kgain2 >>> >>> aL = aLkgain2 >>> >>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>> >>> acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>> acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 >>> acL butterhp acL, 70 >>> acL reson acL, ifr, ifr/10 >>> acL balance acL, aL >>> >>> acL = acLkenv >>> >>> apL, apR pan2 acL, krmsrL/1.6 >>> >>> outs apL, apR >>> >>> endin >>> >>> instr 3; reson filter on R channel >>> >>> seed 0 >>> >>> irand random 6, 12.9 >>> >>> kcpsR zkr 2 >>> ifr = i(kcpsR) >>> print ifr >>> >>> aR zar 2 >>> krmsrR zkr 4 >>> >>> kgain3 ctrl7 1, 2, 0, 1 >>> kgain3 portk kgain3, 0.1 >>> outvalue "kgain3", kgain3 >>> >>> aR = aRkgain3 >>> >>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>> >>> acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>> acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 >>> acR butterhp acR, 70 >>> acR reson aR, ifr, ifr/10 >>> acR balance acR, aR >>> >>> acR = acRkenv >>> >>> apL, apR pan2 acR, 1-(krmsrR/1.6) >>> >>> outs apL, apR >>> >>> endin >>> >>> >>> >>> >>> >>> f1 0 16384 10 1 >>> >>> i 1 0 140 >>> i 2 0 140 >>> i 3 0 140 >>> >>> e >>> >>> >>> >>> >>> >>> >>> ----- >>> Christos Carras >>> -- >>> View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html >>> Sent from the Csound - General mailing list archive at Nabble.com. >>> >>> Csound mailing list >>> Csound@listserv.heanet.ie >>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>> Send bugs reports to >>> https://github.com/csound/csound/issues >>> Discussions of bugs and features can be posted here >> >> Csound mailing list >> Csound@listserv.heanet.ie >> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >> Send bugs reports to >> https://github.com/csound/csound/issues >> Discussions of bugs and features can be posted here > > > > -- > > Oeyvind Brandtsegg > Professor of Music Technology > NTNU > 7491 Trondheim > Norway > Cell: +47 92 203 205 > > http://flyndresang.no/ > http://www.partikkelaudio.com/ > http://soundcloud.com/brandtsegg > http://soundcloud.com/t-emp > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-09 12:12
From	Oeyvind Brandtsegg
Subject	Re: i()
	So yet another reason to use chnset/get instead of zak? 2015-11-09 10:21 GMT+01:00 Victor Lazzarini : > I am not sure that zak would write to the variable at i-time (it shouldn’t, but it might do). In this case, > the k-variable will be 0 until perf time. If the same instance of instrs 2/3 is reused, then at i-time > the k-variable will have whatever value it held at the final k-cycle in the previous performance. > > ======================== > Dr Victor Lazzarini > Dean of Arts, Celtic Studies and Philosophy, > Maynooth University, > Maynooth, Co Kildare, Ireland > Tel: 00 353 7086936 > Fax: 00 353 1 7086952 > >> On 9 Nov 2015, at 07:48, Oeyvind Brandtsegg wrote: >> >> As Victor and John says the value will be zero the first time (if you >> run instr 2 and 3 at time zero). But if you delay the start of instr 2 >> and 3 until instr 1 have run a few cycles (and writing something to >> the zak channel), then it should work. >> I haven't tried to run the code, but wonder why you start instr 2 and >> 3 from the score and trigger them via schedkwhen? It seems perhaps >> only the schedkwhen triggering is what you want? Also, it is generally >> recommended to use chn channels in place of zak. (zak being an >> intermediate workaround born at a time when chn channels and arrays >> was not implemented in Csound yet). >> >> best >> Oeyvind >> >> 2015-11-08 23:51 GMT+01:00 Victor Lazzarini : >>> I am not sure what you mean in terms of “working”. The value for ifr is going to be 0 whether you >>> use comb or reson. Except that reson will not give you an init error for that. >>> >>> The reason for 0 has already been explained here. It is the value of kcpsL at i-time the first time you >>> run the instrument. You will see that print ifr prints 0. >>> >>> ======================== >>> Dr Victor Lazzarini >>> Dean of Arts, Celtic Studies and Philosophy, >>> Maynooth University, >>> Maynooth, Co Kildare, Ireland >>> Tel: 00 353 7086936 >>> Fax: 00 353 1 7086952 >>> >>>> On 8 Nov 2015, at 22:22, christos wrote: >>>> >>>> sure (but comb doesn't work, reson does, as in the orc below. if is use comb >>>> instead of reson it doesn't work), thanks a lot! : >>>> >>>> >>>> >>>> >>>> >>>> >>>> sr = 44100 >>>> ksmps = 128 >>>> nchnls = 2 >>>> 0dbfs = 1.0 >>>> >>>> zakinit 5, 5 >>>> >>>> >>>> instr 1; >>>> >>>> ktime timeinsts >>>> outvalue "ktime", ktime >>>> >>>> aL, aR soundin "level5.wav" >>>> >>>> ktim line 0, p3, 120 >>>> >>>> kgain1 ctrl7 1, 0, 0, 1 >>>> kgain1 portk kgain1, 0.1 >>>> outvalue "kgain1", kgain1 >>>> >>>> krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" >>>> krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" >>>> >>>> ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL >>>> >>>> if (krmsrL > 1) then >>>> ktrigL = 1 >>>> elseif (krmsrL <1) then >>>> ktrigL = 0 >>>> endif >>>> >>>> if (krmsrR > 1) then >>>> ktrigR = 1 >>>> elseif (krmsrR <1) then >>>> ktrigR = 0 >>>> endif >>>> >>>> schedkwhen ktrigL, 0, 15, 2, 0, 13 >>>> schedkwhen ktrigR, 0, 15, 3, 0, 13 >>>> >>>> outs aLkgain1, aRkgain1 >>>> >>>> zaw aL, 1 >>>> zaw aR, 2 >>>> zkw kcpsL, 1 >>>> zkw kcpsR, 2 >>>> zkw krmsrL, 3 >>>> zkw krmsrR, 4 >>>> >>>> endin >>>> >>>> instr 2; reson filter on L channel >>>> >>>> seed 0 >>>> >>>> irand random 7, 12.9 >>>> >>>> kcpsL zkr 1 >>>> ifr = i(kcpsL) >>>> print ifr >>>> >>>> aL zar 1 >>>> krmsrL zkr 3 >>>> >>>> kgain2 ctrl7 1, 1, 0, 1 >>>> kgain2 portk kgain2, 0.1 >>>> outvalue "kgain2", kgain2 >>>> >>>> aL = aLkgain2 >>>> >>>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>>> >>>> acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>>> acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 >>>> acL butterhp acL, 70 >>>> acL reson acL, ifr, ifr/10 >>>> acL balance acL, aL >>>> >>>> acL = acLkenv >>>> >>>> apL, apR pan2 acL, krmsrL/1.6 >>>> >>>> outs apL, apR >>>> >>>> endin >>>> >>>> instr 3; reson filter on R channel >>>> >>>> seed 0 >>>> >>>> irand random 6, 12.9 >>>> >>>> kcpsR zkr 2 >>>> ifr = i(kcpsR) >>>> print ifr >>>> >>>> aR zar 2 >>>> krmsrR zkr 4 >>>> >>>> kgain3 ctrl7 1, 2, 0, 1 >>>> kgain3 portk kgain3, 0.1 >>>> outvalue "kgain3", kgain3 >>>> >>>> aR = aRkgain3 >>>> >>>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>>> >>>> acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>>> acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 >>>> acR butterhp acR, 70 >>>> acR reson aR, ifr, ifr/10 >>>> acR balance acR, aR >>>> >>>> acR = acRkenv >>>> >>>> apL, apR pan2 acR, 1-(krmsrR/1.6) >>>> >>>> outs apL, apR >>>> >>>> endin >>>> >>>> >>>> >>>> >>>> >>>> f1 0 16384 10 1 >>>> >>>> i 1 0 140 >>>> i 2 0 140 >>>> i 3 0 140 >>>> >>>> e >>>> >>>> >>>> >>>> >>>> >>>> >>>> ----- >>>> Christos Carras >>>> -- >>>> View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html >>>> Sent from the Csound - General mailing list archive at Nabble.com. >>>> >>>> Csound mailing list >>>> Csound@listserv.heanet.ie >>>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>>> Send bugs reports to >>>> https://github.com/csound/csound/issues >>>> Discussions of bugs and features can be posted here >>> >>> Csound mailing list >>> Csound@listserv.heanet.ie >>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>> Send bugs reports to >>> https://github.com/csound/csound/issues >>> Discussions of bugs and features can be posted here >> >> >> >> -- >> >> Oeyvind Brandtsegg >> Professor of Music Technology >> NTNU >> 7491 Trondheim >> Norway >> Cell: +47 92 203 205 >> >> http://flyndresang.no/ >> http://www.partikkelaudio.com/ >> http://soundcloud.com/brandtsegg >> http://soundcloud.com/t-emp >> >> Csound mailing list >> Csound@listserv.heanet.ie >> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >> Send bugs reports to >> https://github.com/csound/csound/issues >> Discussions of bugs and features can be posted here > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here -- Oeyvind Brandtsegg Professor of Music Technology NTNU 7491 Trondheim Norway Cell: +47 92 203 205 http://flyndresang.no/ http://www.partikkelaudio.com/ http://soundcloud.com/brandtsegg http://soundcloud.com/t-emp Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-09 13:24
From	Victor Lazzarini
Subject	Re: i()
	I guess so. ======================== Dr Victor Lazzarini Dean of Arts, Celtic Studies and Philosophy, Maynooth University, Maynooth, Co Kildare, Ireland Tel: 00 353 7086936 Fax: 00 353 1 7086952 > On 9 Nov 2015, at 12:12, Oeyvind Brandtsegg wrote: > > So yet another reason to use chnset/get instead of zak? > > 2015-11-09 10:21 GMT+01:00 Victor Lazzarini : >> I am not sure that zak would write to the variable at i-time (it shouldn’t, but it might do). In this case, >> the k-variable will be 0 until perf time. If the same instance of instrs 2/3 is reused, then at i-time >> the k-variable will have whatever value it held at the final k-cycle in the previous performance. >> >> ======================== >> Dr Victor Lazzarini >> Dean of Arts, Celtic Studies and Philosophy, >> Maynooth University, >> Maynooth, Co Kildare, Ireland >> Tel: 00 353 7086936 >> Fax: 00 353 1 7086952 >> >>> On 9 Nov 2015, at 07:48, Oeyvind Brandtsegg wrote: >>> >>> As Victor and John says the value will be zero the first time (if you >>> run instr 2 and 3 at time zero). But if you delay the start of instr 2 >>> and 3 until instr 1 have run a few cycles (and writing something to >>> the zak channel), then it should work. >>> I haven't tried to run the code, but wonder why you start instr 2 and >>> 3 from the score and trigger them via schedkwhen? It seems perhaps >>> only the schedkwhen triggering is what you want? Also, it is generally >>> recommended to use chn channels in place of zak. (zak being an >>> intermediate workaround born at a time when chn channels and arrays >>> was not implemented in Csound yet). >>> >>> best >>> Oeyvind >>> >>> 2015-11-08 23:51 GMT+01:00 Victor Lazzarini : >>>> I am not sure what you mean in terms of “working”. The value for ifr is going to be 0 whether you >>>> use comb or reson. Except that reson will not give you an init error for that. >>>> >>>> The reason for 0 has already been explained here. It is the value of kcpsL at i-time the first time you >>>> run the instrument. You will see that print ifr prints 0. >>>> >>>> ======================== >>>> Dr Victor Lazzarini >>>> Dean of Arts, Celtic Studies and Philosophy, >>>> Maynooth University, >>>> Maynooth, Co Kildare, Ireland >>>> Tel: 00 353 7086936 >>>> Fax: 00 353 1 7086952 >>>> >>>>> On 8 Nov 2015, at 22:22, christos wrote: >>>>> >>>>> sure (but comb doesn't work, reson does, as in the orc below. if is use comb >>>>> instead of reson it doesn't work), thanks a lot! : >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> sr = 44100 >>>>> ksmps = 128 >>>>> nchnls = 2 >>>>> 0dbfs = 1.0 >>>>> >>>>> zakinit 5, 5 >>>>> >>>>> >>>>> instr 1; >>>>> >>>>> ktime timeinsts >>>>> outvalue "ktime", ktime >>>>> >>>>> aL, aR soundin "level5.wav" >>>>> >>>>> ktim line 0, p3, 120 >>>>> >>>>> kgain1 ctrl7 1, 0, 0, 1 >>>>> kgain1 portk kgain1, 0.1 >>>>> outvalue "kgain1", kgain1 >>>>> >>>>> krmsrL, krmsoL, kerrL, kcpsL lpread ktim, "level5L.lp" >>>>> krmsrR, krmsoR, kerrR, kcpsR lpread ktim, "level5R.lp" >>>>> >>>>> ;printks "krmsrL = %f, kcpsL = %f\\n", 0.5, krmsrL, kcpsL >>>>> >>>>> if (krmsrL > 1) then >>>>> ktrigL = 1 >>>>> elseif (krmsrL <1) then >>>>> ktrigL = 0 >>>>> endif >>>>> >>>>> if (krmsrR > 1) then >>>>> ktrigR = 1 >>>>> elseif (krmsrR <1) then >>>>> ktrigR = 0 >>>>> endif >>>>> >>>>> schedkwhen ktrigL, 0, 15, 2, 0, 13 >>>>> schedkwhen ktrigR, 0, 15, 3, 0, 13 >>>>> >>>>> outs aLkgain1, aRkgain1 >>>>> >>>>> zaw aL, 1 >>>>> zaw aR, 2 >>>>> zkw kcpsL, 1 >>>>> zkw kcpsR, 2 >>>>> zkw krmsrL, 3 >>>>> zkw krmsrR, 4 >>>>> >>>>> endin >>>>> >>>>> instr 2; reson filter on L channel >>>>> >>>>> seed 0 >>>>> >>>>> irand random 7, 12.9 >>>>> >>>>> kcpsL zkr 1 >>>>> ifr = i(kcpsL) >>>>> print ifr >>>>> >>>>> aL zar 1 >>>>> krmsrL zkr 3 >>>>> >>>>> kgain2 ctrl7 1, 1, 0, 1 >>>>> kgain2 portk kgain2, 0.1 >>>>> outvalue "kgain2", kgain2 >>>>> >>>>> aL = aLkgain2 >>>>> >>>>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>>>> >>>>> acL compress aL, aL, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>>>> acL pareq acL, 800, ampdb(-30), sqrt(.5), 2 >>>>> acL butterhp acL, 70 >>>>> acL reson acL, ifr, ifr/10 >>>>> acL balance acL, aL >>>>> >>>>> acL = acLkenv >>>>> >>>>> apL, apR pan2 acL, krmsrL/1.6 >>>>> >>>>> outs apL, apR >>>>> >>>>> endin >>>>> >>>>> instr 3; reson filter on R channel >>>>> >>>>> seed 0 >>>>> >>>>> irand random 6, 12.9 >>>>> >>>>> kcpsR zkr 2 >>>>> ifr = i(kcpsR) >>>>> print ifr >>>>> >>>>> aR zar 2 >>>>> krmsrR zkr 4 >>>>> >>>>> kgain3 ctrl7 1, 2, 0, 1 >>>>> kgain3 portk kgain3, 0.1 >>>>> outvalue "kgain3", kgain3 >>>>> >>>>> aR = aRkgain3 >>>>> >>>>> kenv expseg 0.001, 0.5, 1, irand-0.5, 0.0001 >>>>> >>>>> acR compress aR, aR, 1, 30, 50, 80, 0.01, 0.1, 0.1 >>>>> acR pareq acR, 800, ampdb(-30), sqrt(.5), 2 >>>>> acR butterhp acR, 70 >>>>> acR reson aR, ifr, ifr/10 >>>>> acR balance acR, aR >>>>> >>>>> acR = acRkenv >>>>> >>>>> apL, apR pan2 acR, 1-(krmsrR/1.6) >>>>> >>>>> outs apL, apR >>>>> >>>>> endin >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> f1 0 16384 10 1 >>>>> >>>>> i 1 0 140 >>>>> i 2 0 140 >>>>> i 3 0 140 >>>>> >>>>> e >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> ----- >>>>> Christos Carras >>>>> -- >>>>> View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744952.html >>>>> Sent from the Csound - General mailing list archive at Nabble.com. >>>>> >>>>> Csound mailing list >>>>> Csound@listserv.heanet.ie >>>>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>>>> Send bugs reports to >>>>> https://github.com/csound/csound/issues >>>>> Discussions of bugs and features can be posted here >>>> >>>> Csound mailing list >>>> Csound@listserv.heanet.ie >>>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>>> Send bugs reports to >>>> https://github.com/csound/csound/issues >>>> Discussions of bugs and features can be posted here >>> >>> >>> >>> -- >>> >>> Oeyvind Brandtsegg >>> Professor of Music Technology >>> NTNU >>> 7491 Trondheim >>> Norway >>> Cell: +47 92 203 205 >>> >>> http://flyndresang.no/ >>> http://www.partikkelaudio.com/ >>> http://soundcloud.com/brandtsegg >>> http://soundcloud.com/t-emp >>> >>> Csound mailing list >>> Csound@listserv.heanet.ie >>> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >>> Send bugs reports to >>> https://github.com/csound/csound/issues >>> Discussions of bugs and features can be posted here >> >> Csound mailing list >> Csound@listserv.heanet.ie >> https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND >> Send bugs reports to >> https://github.com/csound/csound/issues >> Discussions of bugs and features can be posted here > > > > -- > > Oeyvind Brandtsegg > Professor of Music Technology > NTNU > 7491 Trondheim > Norway > Cell: +47 92 203 205 > > http://flyndresang.no/ > http://www.partikkelaudio.com/ > http://soundcloud.com/brandtsegg > http://soundcloud.com/t-emp > > Csound mailing list > Csound@listserv.heanet.ie > https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND > Send bugs reports to > https://github.com/csound/csound/issues > Discussions of bugs and features can be posted here Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here

Date	2015-11-09 20:51
From	christos
Subject	Re: i()
	thanks Victor, Oeyvind and John, these replies have clarified the issue. the problem is indeed that the initial pass returns 0, and since i had use 1/irf in the comb, an error was reported. (btw: yes, indeed, no need to have instr 2 & 3 in the score, i was just trying to see if it made a difference to my problem and forgot to delete them...). a good evening to all, christos ----- Christos Carras -- View this message in context: http://csound.1045644.n5.nabble.com/i-tp5744946p5744981.html Sent from the Csound - General mailing list archive at Nabble.com. Csound mailing list Csound@listserv.heanet.ie https://listserv.heanet.ie/cgi-bin/wa?A0=CSOUND Send bugs reports to https://github.com/csound/csound/issues Discussions of bugs and features can be posted here