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Re: [Csnd] unexpected integ offset

Date2011-09-25 04:35
From"Partev Barr Sarkissian"
SubjectRe: [Csnd] unexpected integ offset
Victor,

I think that makes sense. Correct me if I'm wrong, but when you 
mathemtically break down a signal into it's components, with a 
number of Low-Pass filter types, isn't there a DC component in 
there? That Split Side-Band paper you did (in JAES, September
2008 was it?), wasn't there a DC component in the Taylor Series
Expansion you did?


Regards, cheers,
-Partev


================================================================
 

--- Victor.Lazzarini@nuim.ie wrote:

From: Victor.Lazzarini@nuim.ie
To: csound@lists.bath.ac.uk
Subject: Re: [Csnd] unexpected integ offset
Date: Wed, 21 Sep 2011 20:12:18 +0100

The integrtator is an IIR LP filter, so it will produce a signal with
a certain amount of DC as it has a pole at 0Hz. The code assumes this
to  be  about 0.5 and tries to remove it. I'd say a more robust
approach is to use a DC blocker.
Victor
----- Original Message -----
From: ebmtranceboy 
Date: Wednesday, September 21, 2011 6:37 pm
Subject: [Csnd] unexpected integ offset
To: csound@lists.bath.ac.uk
> Hi all,
> Sorry in advance if this is not the right place to ask this kind of
> question.
> I'm trying to understand the following instrument and I'm
> puzzled by the
> "asaw = asawdc - .5" line
>
> ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
> instr 1; band limited sawtooth wave
> ; coded by Josep M Comajuncosas / jan98
> ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
>
>    iamp
> =      10000; intended max. amplitude
>    kenv    linen 1, .2,p3,.2; volume envelope
>    kfreq
> =      cpspch(p4)
>    ibound  =      sr/4;
> set it to sr/2 for true BL square wave
>    apulse  buzz 1, kfreq, ibound/kfreq, 1
>    asawdc integ apulse
>    asaw
> =       asawdc - .5
>               out     asawdc*iamp*kenv
> endin
>
>  Indeed, if the fundamental period is 2pi and N the number of
required
> harmonics (ibound/kfreq in instr 1), buzz opcode provides a
> signal (assumely
> continuous)
>
>                                   b(t) = (sum { cos(kt), k = 1..
N}) / N
>
> so, by integration,
>
>                             saw(t) = integ [b(u)du, u = 0..t]
>                             saw(t) = (sum { sin(kt) / k, k = 1..
N}) / N
>
> which is precisely the reconstruction of the signal whose Fourier
> coefficients are (N times smaller than) (1,1/2,1/3,...,1/N) that
> is just the
> asaw signal we're trying to build and I don't understand where
> the 1/2
> offset comes from.
>
> Is it a numerical (discrete signal) consequence ? If so, why
> this 1/2
> coefficient doesn't depend of N (setting ibound to sr/2 for
> example still
> requires the offset set to 1/2 to get the asaw expected).
>
> Help me with my maths please!
>
>
>
> --
> View this message in context:
> http://csound.1045644.n5.nabble.com/unexpected-integ-offset-
> tp4827197p4827197.htmlSent from the Csound - General mailing
> list archive at Nabble.com.
>
>
> Send bugs reports to the Sourceforge bug tracker
>
https://sourceforge.net/tracker/?group_id=81968&atid=564599
> Discussions of bugs and features can be posted here
> To unsubscribe, send email sympa@lists.bath.ac.uk with body
> "unsubscribe csound"
>
Dr Victor Lazzarini, Senior Lecturer, Dept. of Music,
National University of Ireland, Maynooth




_____________________________________________________________
Netscape.  Just the Net You Need.


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Date2011-09-25 10:24
FromVictor Lazzarini
SubjectRe: [Csnd] unexpected integ offset
yes, there is a DC and that is what the code tries to remove. But I  
would use a DC blocker instead.

Victor
On 25 Sep 2011, at 04:35, Partev Barr Sarkissian wrote:

> Victor,
>
> I think that makes sense. Correct me if I'm wrong, but when you
> mathemtically break down a signal into it's components, with a
> number of Low-Pass filter types, isn't there a DC component in
> there? That Split Side-Band paper you did (in JAES, September
> 2008 was it?), wasn't there a DC component in the Taylor Series
> Expansion you did?
>
>
> Regards, cheers,
> -Partev
>
>
> ================================================================
>
>
> --- Victor.Lazzarini@nuim.ie wrote:
>
> From: Victor.Lazzarini@nuim.ie
> To: csound@lists.bath.ac.uk
> Subject: Re: [Csnd] unexpected integ offset
> Date: Wed, 21 Sep 2011 20:12:18 +0100
>
> The integrtator is an IIR LP filter, so it will produce a signal with
> a certain amount of DC as it has a pole at 0Hz. The code assumes this
> to  be  about 0.5 and tries to remove it. I'd say a more robust
> approach is to use a DC blocker.
> Victor
> ----- Original Message -----
> From: ebmtranceboy 
> Date: Wednesday, September 21, 2011 6:37 pm
> Subject: [Csnd] unexpected integ offset
> To: csound@lists.bath.ac.uk
>> Hi all,
>> Sorry in advance if this is not the right place to ask this kind of
>> question.
>> I'm trying to understand the following instrument and I'm
>> puzzled by the
>> "asaw = asawdc - .5" line
>>
>> ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
>> instr 1; band limited sawtooth wave
>> ; coded by Josep M Comajuncosas / jan98
>> ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
>>
>>   iamp
>> =      10000; intended max. amplitude
>>   kenv    linen 1, .2,p3,.2; volume envelope
>>   kfreq
>> =      cpspch(p4)
>>   ibound  =      sr/4;
>> set it to sr/2 for true BL square wave
>>   apulse  buzz 1, kfreq, ibound/kfreq, 1
>>   asawdc integ apulse
>>   asaw
>> =       asawdc - .5
>>              out     asawdc*iamp*kenv
>> endin
>>
>> Indeed, if the fundamental period is 2pi and N the number of
> required
>> harmonics (ibound/kfreq in instr 1), buzz opcode provides a
>> signal (assumely
>> continuous)
>>
>>                                  b(t) = (sum { cos(kt), k = 1..
> N}) / N
>>
>> so, by integration,
>>
>>                            saw(t) = integ [b(u)du, u = 0..t]
>>                            saw(t) = (sum { sin(kt) / k, k = 1..
> N}) / N
>>
>> which is precisely the reconstruction of the signal whose Fourier
>> coefficients are (N times smaller than) (1,1/2,1/3,...,1/N) that
>> is just the
>> asaw signal we're trying to build and I don't understand where
>> the 1/2
>> offset comes from.
>>
>> Is it a numerical (discrete signal) consequence ? If so, why
>> this 1/2
>> coefficient doesn't depend of N (setting ibound to sr/2 for
>> example still
>> requires the offset set to 1/2 to get the asaw expected).
>>
>> Help me with my maths please!
>>
>>
>>
>> --
>> View this message in context:
>> http://csound.1045644.n5.nabble.com/unexpected-integ-offset-
>> tp4827197p4827197.htmlSent from the Csound - General mailing
>> list archive at Nabble.com.
>>
>>
>> Send bugs reports to the Sourceforge bug tracker
>>
> https://sourceforge.net/tracker/?group_id=81968&atid=564599
>> Discussions of bugs and features can be posted here
>> To unsubscribe, send email sympa@lists.bath.ac.uk with body
>> "unsubscribe csound"
>>
> Dr Victor Lazzarini, Senior Lecturer, Dept. of Music,
> National University of Ireland, Maynooth
>
>
>
>
> _____________________________________________________________
> Netscape.  Just the Net You Need.
>
>
> Send bugs reports to the Sourceforge bug tracker
>            https://sourceforge.net/tracker/?group_id=81968&atid=564599
> Discussions of bugs and features can be posted here
> To unsubscribe, send email sympa@lists.bath.ac.uk with body  
> "unsubscribe csound"
>

Dr Victor Lazzarini
Senior Lecturer
Dept. of Music
NUI Maynooth Ireland
tel.: +353 1 708 3545
Victor dot Lazzarini AT nuim dot ie





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