[Csnd] another loop question

[Csnd] another loop question

Date	2012-07-29 01:00
From	peiman khosravi
Subject	[Csnd] another loop question
	Hello, I understand that a k-rate loop block will perform all the iterations once per k-cycle (?). So what happens when one puts an opcode with a k rate output inside a loop block? Something like this: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1

Date	2012-07-29 11:06
From	joachim heintz
Subject	Re: [Csnd] another loop question
	hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: -n instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin i 1 0 10 i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: > > kcount=0 > > loop: > > kline line 0, 10, 1 > > if (kcount<10) kgoto loop > > kcount=kcount+1

Date	2012-07-29 11:18
From	peiman khosravi
Subject	Re: [Csnd] another loop question
	Thanks very much Joachim. Wow, I had no idea. Glad I asked! Are the increments evened out over the duration of a full loop cycle? Or is there one increment per iteration? Best, Peiman On 29 July 2012 11:06, joachim heintz <jh@joachimheintz.de> wrote: hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1 Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2012-07-29 11:30
From	peiman khosravi
Subject	Re: [Csnd] another loop question
	Aha, the actual rate depends on the control rate. This seems to work out as one increment per k cycle. kline line 0, 1/kr, 1 On 29 July 2012 11:18, peiman khosravi <peimankhosravi@gmail.com> wrote: Thanks very much Joachim. Wow, I had no idea. Glad I asked! Are the increments evened out over the duration of a full loop cycle? Or is there one increment per iteration? Best, Peiman On 29 July 2012 11:06, joachim heintz <jh@joachimheintz.de> wrote: hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1 Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2012-07-29 17:52
From	Louis Cohen
Subject	Re: [Csnd] another loop question
	Pieman, There is a problem with your code. It starts with the line: kcount = 0 This causes kcount to be set to 0 every k-cycle. So you will set kcount to 0, then later increment by 1, then set it to 0 again and so forth. It will never get higher than 1. If you want kcount to increase from one k-cycle to the next, you must instead write kcount init 0 This sets kcount to 0 only once at init time. then kcount = kcount + 1 will cause kcount to increase by 1 every k-cycle. -Lou Cohen On Jul 29, 2012, at 6:30 AM, peiman khosravi wrote: > Aha, the actual rate depends on the control rate. This seems to work > out as one increment per k cycle. > > kline line 0, 1/kr, 1 > > > On 29 July 2012 11:18, peiman khosravi > wrote: > Thanks very much Joachim. Wow, I had no idea. Glad I asked! > > Are the increments evened out over the duration of a full loop > cycle? Or is there one increment per iteration? > > Best, > Peiman > > > On 29 July 2012 11:06, joachim heintz wrote: > hi peiman - > > i think you must put the line > kcount = kcount + 1 > before the if statement. > > what you then get, is a faster increment, because in every k-cycle > the kline variable is incremented ten times: > > > > -n > > > instr 1 > > kcount=0 > loop: > kline line 0, 10, 1 > kcount=kcount+1 > > if (kcount<10) kgoto loop > printk .1, kline > endin > > > i 1 0 10 > > > > i 1 time 1.00000: 0.99998 > i 1 time 2.00000: 1.99998 > i 1 time 3.00000: 2.99998 > i 1 time 4.00000: 3.99998 > i 1 time 5.00000: 4.99998 > i 1 time 6.00000: 5.99998 > i 1 time 7.00000: 6.99998 > i 1 time 8.00000: 7.99998 > i 1 time 9.00000: 8.99998 > i 1 time 10.00000: 9.99998 > > so you are able to make time to run faster ... > > best - > > joachim > > > > Am 29.07.2012 02:00, schrieb peiman khosravi: > > > kcount=0 > > loop: > > kline line 0, 10, 1 > > if (kcount<10) kgoto loop > > kcount=kcount+1 > > > Send bugs reports to the Sourceforge bug tracker > https://sourceforge.net/tracker/?group_id=81968&atid=564599 > Discussions of bugs and features can be posted here > To unsubscribe, send email sympa@lists.bath.ac.uk with body > "unsubscribe csound" > > >

Date	2012-07-30 00:05
From	peiman khosravi
Subject	Re: [Csnd] another loop question
	Thanks Lou, I see your point, but wouldn't that give a different result? From what I understand at the moment kcount is set to 0 on the first k cycle. Then we enter the loop section and complete the iterations up to 10, still only in the first k cycle. Then on the second cycle kcount is set to zero again and we recount to ten before the next cycle. So I think the difference is that with '=' the count is wrapping around where as with 'init' it keeps incrementing up. My question is why this instrument below keeps counting even passed 10. With the conditional there shouldn't the count stop at 10? <CsoundSynthesizer> <CsOptions> -n -odac -d </CsOptions> <CsInstruments> sr = 44100 ksmps = 100 nchnls = 1 instr 1 kcount init 0 loop: printk2 kcount kcount=kcount+1 if (kcount<10) kgoto loop endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> On 29 July 2012 17:52, Louis Cohen <loucohen@jolc.net> wrote: Pieman, There is a problem with your code. It starts with the line: kcount = 0 This causes kcount to be set to 0 every k-cycle. So you will set kcount to 0, then later increment by 1, then set it to 0 again and so forth. It will never get higher than 1. If you want kcount to increase from one k-cycle to the next, you must instead write kcount init 0 This sets kcount to 0 only once at init time. then kcount = kcount + 1 will cause kcount to increase by 1 every k-cycle. -Lou Cohen On Jul 29, 2012, at 6:30 AM, peiman khosravi wrote: Aha, the actual rate depends on the control rate. This seems to work out as one increment per k cycle. kline line 0, 1/kr, 1 On 29 July 2012 11:18, peiman khosravi <peimankhosravi@gmail.com> wrote: Thanks very much Joachim. Wow, I had no idea. Glad I asked! Are the increments evened out over the duration of a full loop cycle? Or is there one increment per iteration? Best, Peiman On 29 July 2012 11:06, joachim heintz <jh@joachimheintz.de> wrote: hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1 Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound" Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2012-07-30 00:16
From	peiman khosravi
Subject	Re: [Csnd] another loop question
	BTW I realise that 'kline line 0, 1/kr, 1' mentioned in one of my previous emails is totally absurd. 1/kr is not in seconds! P On 30 July 2012 00:05, peiman khosravi <peimankhosravi@gmail.com> wrote: Thanks Lou, I see your point, but wouldn't that give a different result? From what I understand at the moment kcount is set to 0 on the first k cycle. Then we enter the loop section and complete the iterations up to 10, still only in the first k cycle. Then on the second cycle kcount is set to zero again and we recount to ten before the next cycle. So I think the difference is that with '=' the count is wrapping around where as with 'init' it keeps incrementing up. My question is why this instrument below keeps counting even passed 10. With the conditional there shouldn't the count stop at 10? <CsoundSynthesizer> <CsOptions> -n -odac -d </CsOptions> <CsInstruments> sr = 44100 ksmps = 100 nchnls = 1 instr 1 kcount init 0 loop: printk2 kcount kcount=kcount+1 if (kcount<10) kgoto loop endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> On 29 July 2012 17:52, Louis Cohen <loucohen@jolc.net> wrote: Pieman, There is a problem with your code. It starts with the line: kcount = 0 This causes kcount to be set to 0 every k-cycle. So you will set kcount to 0, then later increment by 1, then set it to 0 again and so forth. It will never get higher than 1. If you want kcount to increase from one k-cycle to the next, you must instead write kcount init 0 This sets kcount to 0 only once at init time. then kcount = kcount + 1 will cause kcount to increase by 1 every k-cycle. -Lou Cohen On Jul 29, 2012, at 6:30 AM, peiman khosravi wrote: Aha, the actual rate depends on the control rate. This seems to work out as one increment per k cycle. kline line 0, 1/kr, 1 On 29 July 2012 11:18, peiman khosravi <peimankhosravi@gmail.com> wrote: Thanks very much Joachim. Wow, I had no idea. Glad I asked! Are the increments evened out over the duration of a full loop cycle? Or is there one increment per iteration? Best, Peiman On 29 July 2012 11:06, joachim heintz <jh@joachimheintz.de> wrote: hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1 Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound" Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2012-07-30 09:27
From	joachim heintz
Subject	Re: [Csnd] another loop question
	this is what happens: - in the first k-cycle kcount is incremented ten times because of the loop condition. - in the following k-cycles it continues to increment because of the statement 'kcount=kcount+1', but it increments just once in one k-cycle. see the output below. best - j -n ksmps = 100 instr 1 kNum timeinstk ;reports number of k-cycle kcount init 0 loop: printk2 kcount kcount=kcount+1 if (kcount<10) kgoto loop printks "Number of k-cycle = %d, kcount = %d\n", 0, kNum, kcount endin i 1 0 .1 SECTION 1: new alloc for instr 1: i1 0.00000 i1 1.00000 i1 2.00000 i1 3.00000 i1 4.00000 i1 5.00000 i1 6.00000 i1 7.00000 i1 8.00000 i1 9.00000 Number of k-cycle = 1, kcount = 10 i1 10.00000 Number of k-cycle = 2, kcount = 11 i1 11.00000 Number of k-cycle = 3, kcount = 12 i1 12.00000 Number of k-cycle = 4, kcount = 13 i1 13.00000 Number of k-cycle = 5, kcount = 14 i1 14.00000 Number of k-cycle = 6, kcount = 15 i1 15.00000 ... Am 30.07.2012 01:05, schrieb peiman khosravi: > Thanks Lou, > > I see your point, but wouldn't that give a different result? > > From what I understand at the moment kcount is set to 0 on the first k > cycle. Then we enter the loop section and complete the iterations up to > 10, still only in the first k cycle. Then on the second cycle kcount is > set to zero again and we recount to ten before the next cycle. > > So I think the difference is that with '=' the count is wrapping around > where as with 'init' it keeps incrementing up. > > My question is why this instrument below keeps counting even passed 10. > With the conditional there shouldn't the count stop at 10? > > > > -n -odac -d > > > > sr = 44100 > ksmps = 100 > nchnls = 1 > > instr 1 > > kcount init 0 > loop: > > printk2 kcount > > kcount=kcount+1 > > if (kcount<10) kgoto loop > > > endin > > > > i 1 0 10 > > > > > On 29 July 2012 17:52, Louis Cohen > wrote: > > Pieman, > > There is a problem with your code. It starts with the line: > > kcount = 0 > > This causes kcount to be set to 0 every k-cycle. So you will set > kcount to 0, then later increment by 1, then set it to 0 again and > so forth. It will never get higher than 1. > > If you want kcount to increase from one k-cycle to the next, you > must instead write > > kcount init 0 > > This sets kcount to 0 only once at init time. then > > > kcount = kcount + 1 > > will cause kcount to increase by 1 every k-cycle. > > -Lou Cohen > > > On Jul 29, 2012, at 6:30 AM, peiman khosravi wrote: > > Aha, the actual rate depends on the control rate. This seems to > work out as one increment per k cycle. > > kline line 0, 1/kr, 1 > > > On 29 July 2012 11:18, peiman khosravi > wrote: > Thanks very much Joachim. Wow, I had no idea. Glad I asked! > > Are the increments evened out over the duration of a full loop > cycle? Or is there one increment per iteration? > > Best, > Peiman > > > On 29 July 2012 11:06, joachim heintz > wrote: > hi peiman - > > i think you must put the line > kcount = kcount + 1 > before the if statement. > > what you then get, is a faster increment, because in every > k-cycle the kline variable is incremented ten times: > > > > -n > > > instr 1 > > kcount=0 > loop: > kline line 0, 10, 1 > kcount=kcount+1 > > if (kcount<10) kgoto loop > printk .1, kline > endin > > > i 1 0 10 > > > > i 1 time 1.00000: 0.99998 > i 1 time 2.00000: 1.99998 > i 1 time 3.00000: 2.99998 > i 1 time 4.00000: 3.99998 > i 1 time 5.00000: 4.99998 > i 1 time 6.00000: 5.99998 > i 1 time 7.00000: 6.99998 > i 1 time 8.00000: 7.99998 > i 1 time 9.00000: 8.99998 > i 1 time 10.00000: 9.99998 > > so you are able to make time to run faster ... > > best - > > joachim > > > > Am 29.07.2012 02:00, schrieb peiman khosravi: > > > kcount=0 > > loop: > > kline line 0, 10, 1 > > if (kcount<10) kgoto loop > > kcount=kcount+1 > > > Send bugs reports to the Sourceforge bug tracker > https://sourceforge.net/__tracker/?group_id=81968&atid=__564599 > > Discussions of bugs and features can be posted here > To unsubscribe, send email sympa@lists.bath.ac.uk > with body "unsubscribe csound" > > > > > > > Send bugs reports to the Sourceforge bug tracker > https://sourceforge.net/__tracker/?group_id=81968&atid=__564599 > > Discussions of bugs and features can be posted here > To unsubscribe, send email sympa@lists.bath.ac.uk > with body "unsubscribe csound" > >

Date	2012-07-30 09:40
From	peiman khosravi
Subject	Re: [Csnd] another loop question
	Ah yes this makes perfect sense. Thanks joachim. Best, Peiman On 30 July 2012 09:27, joachim heintz <jh@joachimheintz.de> wrote: this is what happens: - in the first k-cycle kcount is incremented ten times because of the loop condition. - in the following k-cycles it continues to increment because of the statement 'kcount=kcount+1', but it increments just once in one k-cycle. see the output below. best - j <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> ksmps = 100 instr 1 kNum timeinstk ;reports number of k-cycle kcount init 0 loop: printk2 kcount kcount=kcount+1 if (kcount<10) kgoto loop printks "Number of k-cycle = %d, kcount = %d\n", 0, kNum, kcount endin </CsInstruments> <CsScore> i 1 0 .1 </CsScore> </CsoundSynthesizer> SECTION 1: new alloc for instr 1: i1 0.00000 i1 1.00000 i1 2.00000 i1 3.00000 i1 4.00000 i1 5.00000 i1 6.00000 i1 7.00000 i1 8.00000 i1 9.00000 Number of k-cycle = 1, kcount = 10 i1 10.00000 Number of k-cycle = 2, kcount = 11 i1 11.00000 Number of k-cycle = 3, kcount = 12 i1 12.00000 Number of k-cycle = 4, kcount = 13 i1 13.00000 Number of k-cycle = 5, kcount = 14 i1 14.00000 Number of k-cycle = 6, kcount = 15 i1 15.00000 ... Am 30.07.2012 01:05, schrieb peiman khosravi: Thanks Lou, I see your point, but wouldn't that give a different result? From what I understand at the moment kcount is set to 0 on the first k cycle. Then we enter the loop section and complete the iterations up to 10, still only in the first k cycle. Then on the second cycle kcount is set to zero again and we recount to ten before the next cycle. So I think the difference is that with '=' the count is wrapping around where as with 'init' it keeps incrementing up. My question is why this instrument below keeps counting even passed 10. With the conditional there shouldn't the count stop at 10? <CsoundSynthesizer> <CsOptions> -n -odac -d </CsOptions> <CsInstruments> sr = 44100 ksmps = 100 nchnls = 1 instr 1 kcount init 0 loop: printk2 kcount kcount=kcount+1 if (kcount<10) kgoto loop endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> On 29 July 2012 17:52, Louis Cohen <loucohen@jolc.net <mailto:loucohen@jolc.net>> wrote: Pieman, There is a problem with your code. It starts with the line: kcount = 0 This causes kcount to be set to 0 every k-cycle. So you will set kcount to 0, then later increment by 1, then set it to 0 again and so forth. It will never get higher than 1. If you want kcount to increase from one k-cycle to the next, you must instead write kcount init 0 This sets kcount to 0 only once at init time. then kcount = kcount + 1 will cause kcount to increase by 1 every k-cycle. -Lou Cohen On Jul 29, 2012, at 6:30 AM, peiman khosravi wrote: Aha, the actual rate depends on the control rate. This seems to work out as one increment per k cycle. kline line 0, 1/kr, 1 On 29 July 2012 11:18, peiman khosravi <peimankhosravi@gmail.com <mailto:peimankhosravi@gmail.com>> wrote: Thanks very much Joachim. Wow, I had no idea. Glad I asked! Are the increments evened out over the duration of a full loop cycle? Or is there one increment per iteration? Best, Peiman On 29 July 2012 11:06, joachim heintz <jh@joachimheintz.de <mailto:jh@joachimheintz.de>> wrote: hi peiman - i think you must put the line kcount = kcount + 1 before the if statement. what you then get, is a faster increment, because in every k-cycle the kline variable is incremented ten times: <CsoundSynthesizer> <CsOptions> -n </CsOptions> <CsInstruments> instr 1 kcount=0 loop: kline line 0, 10, 1 kcount=kcount+1 if (kcount<10) kgoto loop printk .1, kline endin </CsInstruments> <CsScore> i 1 0 10 </CsScore> </CsoundSynthesizer> i 1 time 1.00000: 0.99998 i 1 time 2.00000: 1.99998 i 1 time 3.00000: 2.99998 i 1 time 4.00000: 3.99998 i 1 time 5.00000: 4.99998 i 1 time 6.00000: 5.99998 i 1 time 7.00000: 6.99998 i 1 time 8.00000: 7.99998 i 1 time 9.00000: 8.99998 i 1 time 10.00000: 9.99998 so you are able to make time to run faster ... best - joachim Am 29.07.2012 02:00, schrieb peiman khosravi: kcount=0 loop: kline line 0, 10, 1 if (kcount<10) kgoto loop kcount=kcount+1 Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/__tracker/?group_id=81968&atid=__564599 <https://sourceforge.net/tracker/?group_id=81968&atid=564599> Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk <mailto:sympa@lists.bath.ac.uk> with body "unsubscribe csound" Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/__tracker/?group_id=81968&atid=__564599 <https://sourceforge.net/tracker/?group_id=81968&atid=564599> Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk <mailto:sympa@lists.bath.ac.uk> with body "unsubscribe csound" Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"