sprintf and fractional values [was Re: [Csnd] more python]

sprintf and fractional values [was Re: [Csnd] more python]

Date	2013-04-18 20:04
From	peiman khosravi
Subject	sprintf and fractional values [was Re: [Csnd] more python]
	I'm trying to use the following code (below the email) but the result is this: instr 3: ifrac = 0.100 freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 Now if I change the instrument number to 1 I get this: instr 1: ifrac = 0.100 freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 Have I missed something in the documentation? Thanks P <CsoundSynthesizer> <CsOptions> -odac -d -A -3 -b1024 -B1024 </CsOptions> <CsInstruments> sr = 44100 kr = 4410 ksmps = 10 nchnls = 2 instr 3 ifrac = frac(p1) print ifrac Sfreq sprintf "freq.%g", ifrac prints Sfreq endin </CsInstruments> <CsScore> i3.1 0 1 </CsScore> </CsoundSynthesizer>

Date	2013-04-18 20:14
From	Louis Cohen
Subject	Re: sprintf and fractional values [was Re: [Csnd] more python]
	I'm no expert, but I would guess that 0.0999999B and 0.1B are essentially the same number. -Lou On Apr 18, 2013, at 3:04 PM, peiman khosravi wrote: > I'm trying to use the following code (below the email) but the result is this: > > instr 3: ifrac = 0.100 > freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > Now if I change the instrument number to 1 I get this: > > instr 1: ifrac = 0.100 > freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > > Have I missed something in the documentation? > > Thanks > > P > > > > > > > > -odac -d -A -3 -b1024 -B1024 > > > > sr = 44100 > kr = 4410 > ksmps = 10 > nchnls = 2 > > instr 3 > ifrac = frac(p1) > print ifrac > Sfreq sprintf "freq.%g", ifrac > prints Sfreq > endin > > > > > > i3.1 0 1 > > > > > Lou Cohen www.jolc.net www.opensound.org

Date	2013-04-18 20:16
From	peiman khosravi
Subject	Re: sprintf and fractional values [was Re: [Csnd] more python]
	Not if you're converting them to string after! I'll try rounding it and see what happens. www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 20:14, Louis Cohen <loucohen@jolc.net> wrote: I'm no expert, but I would guess that 0.0999999B and 0.1B are essentially the same number. -Lou On Apr 18, 2013, at 3:04 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: > I'm trying to use the following code (below the email) but the result is this: > > instr 3: ifrac = 0.100 > freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > Now if I change the instrument number to 1 I get this: > > instr 1: ifrac = 0.100 > freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > > Have I missed something in the documentation? > > Thanks > > P > > > > > <CsoundSynthesizer> > > <CsOptions> > -odac -d -A -3 -b1024 -B1024 > </CsOptions> > > <CsInstruments> > sr = 44100 > kr = 4410 > ksmps = 10 > nchnls = 2 > > instr 3 > ifrac = frac(p1) > print ifrac > Sfreq sprintf "freq.%g", ifrac > prints Sfreq > endin > > </CsInstruments> > > > <CsScore> > i3.1 0 1 > </CsScore> > > > </CsoundSynthesizer> > Lou Cohen www.jolc.net www.opensound.org Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2013-04-18 22:09
From	Justin Smith
Subject	Re: sprintf and fractional values [was Re: [Csnd] more python]
	frac(3.1) and frac(1.1) are different numbers in ieee floating point if you are using 32 bit precision On Thu, Apr 18, 2013 at 12:16 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: Not if you're converting them to string after! I'll try rounding it and see what happens. www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 20:14, Louis Cohen <loucohen@jolc.net> wrote: I'm no expert, but I would guess that 0.0999999B and 0.1B are essentially the same number. -Lou On Apr 18, 2013, at 3:04 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: > I'm trying to use the following code (below the email) but the result is this: > > instr 3: ifrac = 0.100 > freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > Now if I change the instrument number to 1 I get this: > > instr 1: ifrac = 0.100 > freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > > Have I missed something in the documentation? > > Thanks > > P > > > > > <CsoundSynthesizer> > > <CsOptions> > -odac -d -A -3 -b1024 -B1024 > </CsOptions> > > <CsInstruments> > sr = 44100 > kr = 4410 > ksmps = 10 > nchnls = 2 > > instr 3 > ifrac = frac(p1) > print ifrac > Sfreq sprintf "freq.%g", ifrac > prints Sfreq > endin > > </CsInstruments> > > > <CsScore> > i3.1 0 1 > </CsScore> > > > </CsoundSynthesizer> > Lou Cohen www.jolc.net www.opensound.org Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2013-04-18 22:10
From	peiman khosravi
Subject	Re: sprintf and fractional values [was Re: [Csnd] more python]
	I see. That makes sense. Thanks for the explanation. I'm using the double version on the desktop computer and that's why it's working there. Cheers, P www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 22:09, Justin Smith <noisesmith@gmail.com> wrote: frac(3.1) and frac(1.1) are different numbers in ieee floating point if you are using 32 bit precision On Thu, Apr 18, 2013 at 12:16 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: Not if you're converting them to string after! I'll try rounding it and see what happens. www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 20:14, Louis Cohen <loucohen@jolc.net> wrote: I'm no expert, but I would guess that 0.0999999B and 0.1B are essentially the same number. -Lou On Apr 18, 2013, at 3:04 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: > I'm trying to use the following code (below the email) but the result is this: > > instr 3: ifrac = 0.100 > freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > Now if I change the instrument number to 1 I get this: > > instr 1: ifrac = 0.100 > freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > > Have I missed something in the documentation? > > Thanks > > P > > > > > <CsoundSynthesizer> > > <CsOptions> > -odac -d -A -3 -b1024 -B1024 > </CsOptions> > > <CsInstruments> > sr = 44100 > kr = 4410 > ksmps = 10 > nchnls = 2 > > instr 3 > ifrac = frac(p1) > print ifrac > Sfreq sprintf "freq.%g", ifrac > prints Sfreq > endin > > </CsInstruments> > > > <CsScore> > i3.1 0 1 > </CsScore> > > > </CsoundSynthesizer> > Lou Cohen www.jolc.net www.opensound.org Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"

Date	2013-04-18 22:13
From	Justin Smith
Subject	Re: sprintf and fractional values [was Re: [Csnd] more python]
	just a quick calculation (in my clojure repl, the float function creates a 32 bit number): user> (frac (float 3.1)) 0.09999990463256836 user> (frac (float 1.1)) 0.10000002384185791 On Thu, Apr 18, 2013 at 2:10 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: I see. That makes sense. Thanks for the explanation. I'm using the double version on the desktop computer and that's why it's working there. Cheers, P www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 22:09, Justin Smith <noisesmith@gmail.com> wrote: frac(3.1) and frac(1.1) are different numbers in ieee floating point if you are using 32 bit precision On Thu, Apr 18, 2013 at 12:16 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: Not if you're converting them to string after! I'll try rounding it and see what happens. www.peimankhosravi.co.uk To receive emails about upcoming concerts visit this page & enter your email address in the 'follow' section. On 18 April 2013 20:14, Louis Cohen <loucohen@jolc.net> wrote: I'm no expert, but I would guess that 0.0999999B and 0.1B are essentially the same number. -Lou On Apr 18, 2013, at 3:04 PM, peiman khosravi <peimankhosravi@gmail.com> wrote: > I'm trying to use the following code (below the email) but the result is this: > > instr 3: ifrac = 0.100 > freq.0.0999999B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > Now if I change the instrument number to 1 I get this: > > instr 1: ifrac = 0.100 > freq.0.1B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0 0.0 > > > Have I missed something in the documentation? > > Thanks > > P > > > > > <CsoundSynthesizer> > > <CsOptions> > -odac -d -A -3 -b1024 -B1024 > </CsOptions> > > <CsInstruments> > sr = 44100 > kr = 4410 > ksmps = 10 > nchnls = 2 > > instr 3 > ifrac = frac(p1) > print ifrac > Sfreq sprintf "freq.%g", ifrac > prints Sfreq > endin > > </CsInstruments> > > > <CsScore> > i3.1 0 1 > </CsScore> > > > </CsoundSynthesizer> > Lou Cohen www.jolc.net www.opensound.org Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"