Hello All,
i promise this is the last question for today.

When i use reverb i do something like this

al, ar    reverbsc    gaL, gaR, 0.7, 19000
ifxlev    =    p4
al     =    (al*ifxlev)+(gaL*(1-ifxlev))

i wish to know if i use ifxlev to 0 i will have a 'real' bypass,
i.e. output signal will be the same of input?

Thanks,
ciao,
francesco.


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yes


2011/10/26 francesco :
> Hello All,
> i promise this is the last question for today.
>
> When i use reverb i do something like this
>
> al, ar    reverbsc    gaL, gaR, 0.7, 19000
> ifxlev    =    p4
> al     =    (al*ifxlev)+(gaL*(1-ifxlev))
>
> i wish to know if i use ifxlev to 0 i will have a 'real' bypass,
> i.e. output signal will be the same of input?
>
> Thanks,
> ciao,
> francesco.
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/reverbsc-transparency-tp4939293p4939293.html
> Sent from the Csound - General mailing list archive at Nabble.com.
>
>
> Send bugs reports to the Sourceforge bug tracker
>            https://sourceforge.net/tracker/?group_id=81968&atid=564599
> Discussions of bugs and features can be posted here
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>
>


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I'd say yes, because   (al*0)  = 0

Victor
On 26 Oct 2011, at 11:01, francesco wrote:

> Hello All,
> i promise this is the last question for today.
>
> When i use reverb i do something like this
>
> al, ar    reverbsc    gaL, gaR, 0.7, 19000
> ifxlev    =    p4
> al     =    (al*ifxlev)+(gaL*(1-ifxlev))
>
> i wish to know if i use ifxlev to 0 i will have a 'real' bypass,
> i.e. output signal will be the same of input?
>
> Thanks,
> ciao,
> francesco.
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/reverbsc-transparency-tp4939293p4939293.html
> Sent from the Csound - General mailing list archive at Nabble.com.
>
>
> Send bugs reports to the Sourceforge bug tracker
>            https://sourceforge.net/tracker/?group_id=81968&atid=564599
> Discussions of bugs and features can be posted here
> To unsubscribe, send email sympa@lists.bath.ac.uk with body  
> "unsubscribe csound"
>

Dr Victor Lazzarini
Senior Lecturer
Dept. of Music
NUI Maynooth Ireland
tel.: +353 1 708 3545
Victor dot Lazzarini AT nuim dot ie





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On Wed, 2011-10-26 at 11:42 +0100, Victor Lazzarini wrote:
> I'd say yes, because   (al*0)  = 0
> 
> Victor

i guess that means that no operations are made on the input signal.
So if i want to listen signal with/without reverb i can use ilev like a
bypass.

Thanks, really many thanks, and for today (only!) no more noise by me,
like i promise!

ciao,
francesco.




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