| As I recall it is the root mean square.
Regards,
Mike
----- Original Message -----
From: "Mark Van Peteghem"
To:
Sent: Monday, March 16, 2009 5:10 PM
Subject: [Csnd] Re: balance opcode
> Federico Vanni wrote:
>> i would know the internal operation of the 'balance'
>> opcode.
>>
>> It should be something like that:
>> Take the averages of signals A and B and then divide average B by average
>> A.
>> Multiply the actual A signal by the product of that division. This will
>> make A
>> match the average level of B.
>
> Correct, except that it's not a simple average, but probably the square
> root of the average of the square of the signals, or the average of the
> absolute value of the signal, because the average can be zero or close to
> zero, and therefore not representative for the power in the signal.
>
> --
> Mark
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