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Re: [Csnd] determining FFT size

Date2011-11-19 19:07
From"Partev Barr Sarkissian"
SubjectRe: [Csnd] determining FFT size
Ah,.... as in sinc = sin(x)/x
duh,.... of course, I should've figured.

-Partev

===============================================


--- ljc@internet.com.uy wrote:

From: luis jure 
To: csound list 
Subject: Re: [Csnd] determining FFT size
Date: Fri, 18 Nov 2011 09:39:57 -0200


on 2011-11-17 at 08:50 Richard Dobson wrote:

>"The window is assumed to be symmetric with M total points.  After the 
>initial memory allocation, analWindow always points to the midpoint of 
>the window (or one half sample to the right, if M is even); analWinLen
>is half the true window length (rounded down). Any low pass window will 
>work; a Hamming window is generally fine, but a Kaiser is also 
>available.  If the window duration is longer than the transform (M > N), 
>then the window is multiplied by a sin(x)/x function to meet the 
>condition: analWindow[Ni] = 0 for i != 0."


i see... things are more clear now, although i can't say i fully
understand the rationale behind the technique. definitely a twist compared
with the "plain" phase vocoder techniques i was more or less familiar with.

thanks for the clarifications, richard!

lj


(perhaps a summarized version of this information could make its way into
the manual?)



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