Hello everyone,

perhaps the problem is easier than you think.
Someone has an idea of how to capture the new instant value of gkx when the
condition is satisfied, as in?

this is my idea but does not work,
how can I do?

thanks,

enrico

;=====================




seed	0
girange	=	3
gkx	        init	0

;=====================

instr		1

gkx	trirand	girange

endin

;=====================

instr		2

ktime		timeinsts

if	ktime	>=0	&& ktime < 3	then
print i(gkx)

elseif ktime	>=3	&& ktime < 6	then
print i(gkx)

endif

endin




i1	0	7
i3	.001	6
e





;=====================



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This does not work because gkx is converted to i rate (in instrument 2) 
at the initialisation of the instrument, so it will not take account of 
any changes that occur after the initialization of instrument 2.

This should work. Have I misunderstood you?

instr        2

ktime        timeinsts

     if    ktime >=0 && ktime < 3 then
         printk 0, gkx
     elseif  ktime >=3 && ktime < 6 then
         printk 0, gkx
     endif


endin

If you want to sample just one value then you want have this instead:

instr        2

ktime        timeinsts

print    i(gkx)

     if  ktime==3 then
         printk 0, gkx
     endif

endin



Best,

Peiman


On 14/04/2011 22:00, Enrico Francioni wrote:
> Hello everyone,
>
> perhaps the problem is easier than you think.
> Someone has an idea of how to capture the new instant value of gkx when the
> condition is satisfied, as in?
>
> this is my idea but does not work,
> how can I do?
>
> thanks,
>
> enrico
>
> ;=====================
>
>
>
>
> seed	0
> girange	=	3
> gkx	        init	0
>
> ;=====================
>
> instr		1
>
> gkx	trirand	girange
>
> endin
>
> ;=====================
>
> instr		2
>
> ktime		timeinsts
>
> if	ktime	>=0	&&  ktime<  3	then
> print i(gkx)
>
> elseif ktime	>=3	&&  ktime<  6	then
> print i(gkx)
>
> endif
>
> endin
>
>
>
>
> i1	0	7
> i3	.001	6
> e
>
>
>
>
>
> ;=====================
>
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4304096.html
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>
>
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thanks peiman…

perhaps I have not explained ...

But I would like to have a new instantaneous value (generated with trirand
opcode)
every time I open the condition as in my example...




seed	0 
girange	=	3 
gkx	        init	0 

;===================== 

instr	 1 

gkx	trirand	girange     ; generate a rand values between -3 and +3

endin 

;===================== 

instr	 2 

ktime	 timeinsts 

if	ktime	>=0	&& ktime < 3	then 
print i(gkx)                                       ; istant value after 0
seconds

elseif ktime	>=3	&& ktime < 6	then 
print i(gkx)                                       
; istant value after 3 seconds - [this is likely to be (random) other than
the first]

endif 

endin 




i1	0	7 
i2	.001	6 
e 





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Sorry Enrico,

I still don't quite understand you. trirand is generating values at 
k-rate so you mean you want to sample its output at a specific point in 
time? This example I sent does exactly that:




-odac -d




sr     = 96000
ksmps  = 100
nchnls = 1
0dbfs  = 1

seed    0
girange    =    3
gkx            init    0

;=====================

instr     1

gkx    trirand    girange     ; generate a rand values between -3 and +3

endin

instr        2

ktime        timeinsts

print    i(gkx)

     if  ktime==3 then
         printk 0, gkx
     endif

endin





i1    0    7
i2    .001    6
e








On 15/04/2011 09:06, Enrico Francioni wrote:
> thanks peiman…
>
> perhaps I have not explained ...
>
> But I would like to have a new instantaneous value (generated with trirand
> opcode)
> every time I open the condition as in my example...
>
>
>
>
> seed	0
> girange	=	3
> gkx	        init	0
>
> ;=====================
>
> instr	 1
>
> gkx	trirand	girange     ; generate a rand values between -3 and +3
>
> endin
>
> ;=====================
>
> instr	 2
>
> ktime	 timeinsts
>
> if	ktime	>=0	&&  ktime<  3	then
> print i(gkx)                                       ; istant value after 0
> seconds
>
> elseif ktime	>=3	&&  ktime<  6	then
> print i(gkx)
> ; istant value after 3 seconds - [this is likely to be (random) other than
> the first]
>
> endif
>
> endin
>
>
>
>
> i1	0	7
> i2	.001	6
> e
>
>
>
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4304990.html
> Sent from the Csound - General mailing list archive at Nabble.com.
>
>
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>              https://sourceforge.net/tracker/?group_id=81968&atid=564599
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> To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"
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ok peiman,

but I would like to get this instead:





sr     = 96000 
ksmps  = 100 
nchnls = 1 
0dbfs  = 1 

seed    0 
girange    =    3 
gkx            init    0 

;===================== 

instr     1 

gkx    trirand    girange     ; generate a rand values between -3 and +3 

endin 

instr        2 

ktime        timeinsts 

print    i(gkx) 

     if  ktime==3 then 
         printk 0, gkx 
     

     elseif  ktime==4 then 
         printk 0, gkx 
     

     elseif  ktime==5 then 
         printk 0, gkx 

     elseif  ktime==6 then 
         printk 0, gkx 


     elseif  ktime==7 then 
         printk 0, gkx 

     elseif  ktime==10 then 
         printk 0, gkx 

;   etc…

	endif 


endin 



f0	100
i1    0    60 
i2    .001    60
e 








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It's working here.

On 15/04/2011 11:08, Enrico Francioni wrote:
> ok peiman,
>
> but I would like to get this instead:
>
>
>
>
>
> sr     = 96000
> ksmps  = 100
> nchnls = 1
> 0dbfs  = 1
>
> seed    0
> girange    =    3
> gkx            init    0
>
> ;=====================
>
> instr     1
>
> gkx    trirand    girange     ; generate a rand values between -3 and +3
>
> endin
>
> instr        2
>
> ktime        timeinsts
>
> print    i(gkx)
>
>       if  ktime==3 then
>           printk 0, gkx
>
>
>       elseif  ktime==4 then
>           printk 0, gkx
>
>
>       elseif  ktime==5 then
>           printk 0, gkx
>
>       elseif  ktime==6 then
>           printk 0, gkx
>
>
>       elseif  ktime==7 then
>           printk 0, gkx
>
>       elseif  ktime==10 then
>           printk 0, gkx
>
> ;   etc…
>
> 	endif
>
>
> endin
>
>
>
> f0	100
> i1    0    60
> i2    .001    60
> e
>
>
>
>
>
>
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4305206.html
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>
>
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... unfortunately that is not the solution

e

…

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Hello Mr. Enrico,
Your examples is working here too, like Mr. Peiman sayd.
It is not what are You trying to do?

(IT: da te non funziona o non è il risultato che ti aspetti?)

ciao,
francesco.

My output:

instr 2:  #i0 = 0.000
 i   2 time     3.00000:    -1.45080
 i   2 time     4.00000:     0.73128
 i   2 time     5.00000:    -1.13904
 i   2 time     6.00000:    -0.44148
 i   2 time     7.00000:     0.62064
 i   2 time    10.00000:    -1.59675




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hi francesco!

But I would like to work so that the condition,
and unpack a single process variable (random) from each condition




sr     = 96000 
ksmps  = 100 
nchnls = 1 
0dbfs  = 1 

seed    0 
girange    =    3 
gkx            init    0 

;===================== 

instr     1 

gkx    trirand    girange     ; generate a rand values between -3 and +3 

endin 

instr        2 

ktime        timeinsts 


     if  ktime>=3 && ktime< 4 then 
         printk 0, gkx 
      

     elseif  ktime>=4 && ktime< 5 then 
         printk 0, gkx 
      

     elseif  ktime>= 5 && ktime<6 then 
         printk 0, gkx 

    elseif  ktime>= 6 && ktime<7 then 
         printk 0, gkx 

     elseif  ktime>= 7 && ktime<10 then 
         printk 0, gkx 

    elseif  ktime>= 10 && ktime<12 then 
         printk 0, gkx 

;   etc… 

        endif 


endin 



f0	100 
i1    0    60 
i2    .001    60 
e 







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On 15/04/2011 12:25, Enrico Francioni wrote:
> hi francesco!
>
> But I would like to work so that the condition,
> and unpack a single process variable (random) from each condition
>
>
>
>
> sr     = 96000
> ksmps  = 100
> nchnls = 1
> 0dbfs  = 1
>
> seed    0
> girange    =    3
> gkx            init    0
>
> ;=====================
>
> instr     1
>
> gkx    trirand    girange     ; generate a rand values between -3 and +3
>
> endin
>
> instr        2
>
> ktime        timeinsts
>
>
>       if  ktime>=3&&  ktime<  4 then
>           printk 0, gkx
>
>
>       elseif  ktime>=4&&  ktime<  5 then
>           printk 0, gkx
>
>
>       elseif  ktime>= 5&&  ktime<6 then
>           printk 0, gkx
>
>      elseif  ktime>= 6&&  ktime<7 then
>           printk 0, gkx
>
>       elseif  ktime>= 7&&  ktime<10 then
>           printk 0, gkx
>
>      elseif  ktime>= 10&&  ktime<12 then
>           printk 0, gkx
>
> ;   etc…
>
>          endif
>
>
> endin
>
>
>
> f0	100
> i1    0    60
> i2    .001    60
> e
>
>
>
>
>
>
>
> --
> View this message in context: http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4305322.html
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>
Do you mean something like this:

instr        2

ktime        timeinsts


      if  ktime>=3 && ktime< 4 then
          reinit pass

      elseif  ktime>=4 && ktime< 5 then
          reinit pass

      elseif  ktime>= 5 && ktime<6 then
          reinit pass

     elseif  ktime>= 6 && ktime<7 then
          reinit pass

      elseif  ktime>= 7 && ktime<10 then
          reinit pass

     elseif  ktime>= 10 && ktime<12 then
          reinit pass
     endif

pass:

gikx    trirand    girange     ; generate a rand values between -3 and +3
     print     gikx


endin


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but You are doing this, if i'm right.
The random variable gkx is changing at krate in instr 1, and
every time the condition in instr 2 is satisfy You print the value
at this time.

(while i'm writing Mr. Peiman have a solution, maybe the right solution for
You)

ciao,
francesco.


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yes, francesco

for example, it is clear that in this case:

if ktime >= 3 && ktime <= 4 then

the istant value i(gkx) will be captured at second 3,

yes?

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I think yes ... (but many times i wrong!)

Maybe Mr. Peiman could confirm if we are right.

ciao,
francesco.


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No because you're using a krate conditional. So the value will keep 
being captured until ktime==4. So you get a printout on every control 
period during this time.

P



On 15/04/2011 12:50, Enrico Francioni wrote:
> yes, francesco
>
> for example, it is clear that in this case:
>
> if ktime>= 3&&  ktime<= 4 then
>
> the istant value i(gkx) will be captured at second 3,
>
> yes?
>
> --
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>
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Sorry Mr. Peiman,
You are referring to Your last example, am i right?

thanks,
ciao,
francesco.


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ok peiman,

but the press of the values ​​k I extract only the first instantaneous value
(i)
without limiting the condition to a single value:
k1 ; only this value is my desired capture!
k2
k3
k4
k5
k6
k7
k8
k9
k10
k ...
kN

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I think what you want here is best done with the samphold and metro opcodes.






sr	=	96000
ksmps	=	100
nchnls	=	1
0dbfs	=	1

	seed	0
girange	=	3 
gkx	init	0 

	instr	1 
gkx	trirand	girange     ; generate a rand values between -3 and +3 
	endin 

	instr	2 
ktrig	metro 1			; triggers once per second
kval	samphold gkx, ktrig	; change value whenever ktrig = 1
	printk2 kval		; will print every time kval changes
	endin



i 1 0 10
i 2 .1 10




Enrico Francioni wrote:
> ok peiman,
> 
> but the press of the values ​​k I extract only the first instantaneous value
> (i)
> without limiting the condition to a single value:
> k1 ; only this value is my desired capture!
> k2
> k3
> k4
> k5
> k6
> k7
> k8
> k9
> k10
> k ...
> kN
> 
> --
> View this message in context: http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4305396.html
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> 
> 
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> 
> 



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Hello,

I was refering to Enrico's example.

Best,

Peiman

On 15 April 2011 13:05, francesco  wrote:
> Sorry Mr. Peiman,
> You are referring to Your last example, am i right?
>
> thanks,
> ciao,
> francesco.
>
>
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Another comment:
i() does not mean "instantaneous", it means "initialization", it is for capturing the value of a variable when an instrument starts. If the variable should change value without restarting the instrument you need a k variable. If restarting the instrument is acceptable you can do the same thing with reinit.

The following snippets all do pretty much the same thing:

1)
kval samphold gkin, ktrig
2)
kval init 0
kval = (ktrig == 0) ? kval : gkin
3)
kval init 0
if (ktrig == 0) kgoto nochange
kval = gkin
nochange:
4)
restart:
ival = i(gkin)
if (ktrig == 0) kgoto cont
reinit restart
cont:

I have sorted them based on line count, all other things being equal I personally go with the solution with the smaller line count.

----- Original message -----
> ok peiman,
>
> but the press of the values ​​k I extract only the first instantaneous
> value (i)
> without limiting the condition to a single value:
> k1 ; only this value is my desired capture!
> k2
> k3
> k4
> k5
> k6
> k7
> k8
> k9
> k10
> k ...
> kN
>
> --
> View this message in context:
> http://csound.1045644.n5.nabble.com/instant-value-tp4304096p4305396.html
> Sent from the Csound - General mailing list archive at Nabble.com.
>
>
> Send bugs reports to the Sourceforge bug tracker
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OK Justin,

on line of the solution devised by peiman (thanks peiman), I think your
solution number 4 is what I wanted to do;
Obviously the timing of ktrigger them could determine the opcode linseg …or
a table

for example:

instr	2
ival	init	0
ktrig		linseg	1, .0001, 0, 2.5, 0, .0001, 1, .0001, 0, 3, 0, .0001, 1,
.0001, 0,  1.5, 0, .0001, 1, .0001, 0, 2, 0, .0001, 1, .0001, 0, 1, 0

restart: 
ival = i(gkx) 
if (ktrig == 0) kgoto cont 
reinit restart 
cont: 

print		ival

endin


many thanks

e

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