Your assumption is not correct, because a-rate and k-rate are the same. The
difference is that an a-rate VARIABLE 
(at ksmps > 1) is a vector, whereas a k-rate VARIABLE is always a scalar.
But the expression is evaluated once per 
kperiod in both cases.

Hope this helps,
Mike

Original Message:
-----------------
From: Atte André Jensen atte.jensen@gmail.com
Date: Sun, 23 Dec 2007 00:03:28 +0100
To: csound@lists.bath.ac.uk
Subject: [Csnd] basic k-rate question


Hi

Am I correct in assuming that the following (at ksmps > 1):

kdrift	=	1 + klfo * idrift
aosc	vco2	10000, ifreq * kdrift

is cheaper than:

aosc	vco2	10000, ifreq * (1 + klfo * idrift)

My guess is that in the second version "1 + klfo * idrift" gets 
calculated at a-rate, whereas in the first version it gets calculated at 
k-rate, is that correct?

-- 
peace, love & harmony
Atte

http://atte.dk       | http://myspace.com/attejensen
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