Hi,

I got inspired by Victor's tanh() ideas and found this remarkable formula

2*x-1-tanh(a*(2*x-1))/tanh(a)

If x is a phasor going from 0 to 1, this gives an approximate sawtooth  
with roughly 2*a harmonics, when a is about 3.5 or greater. Try it!

Is this known?

Kalle




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