You're right Menno, don't read this message! Here is the correct equadiff, what I have written (too quickly) in the preceding messages is *wrong* (karma police don't arrest me) REMEMBER: kfco is not in Hz y(n) = coef2 * (x(n) + coef1 * y(n-1) - k * y(n-2)) with kfco = kfcobase * (1 + (j*sep / iord)) with j from 0 to (iord - 1) b = 10 / (kres * sqrt(kfco)) - 1 k = 1000 / kfco coeff1 = b+2*k coeff2 = 1/(1+b+k) A fridge man On Sun, Nov 20, 2011 at 08:24:34AM -0800, menno wrote: > thanks Victor > and > thanks Tito, but that will take me 2 life times to understand :) > my maths are like the temperature outside: nearly zero > but really thanks. > > Menno > > > -- > View this message in context: http://csound.1045644.n5.nabble.com/frequency-cutoff-separation-tp5008229p5008403.html > Sent from the Csound - General mailing list archive at Nabble.com. > > > Send bugs reports to the Sourceforge bug tracker > https://sourceforge.net/tracker/?group_id=81968&atid=564599 > Discussions of bugs and features can be posted here > To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound" Send bugs reports to the Sourceforge bug tracker https://sourceforge.net/tracker/?group_id=81968&atid=564599 Discussions of bugs and features can be posted here To unsubscribe, send email sympa@lists.bath.ac.uk with body "unsubscribe csound"