Are volatile C strings printed in C++ by special rules?  See the
comments at the end of the following C++ program.

John

vcp.cc:
---------------------------------------------------
#include 
#include 

int main(int argc, char **argv)
{
  volatile char str[] = { 'a', 'b', '\0' };
  std::printf("%s\n", str);
  std::cout << str << "\n";
  return 0;
}

/*
 * $ uname -a
 * Linux localhost.localdomain 2.6.5-1.358 #1 Sat May 8 09:04:50 EDT 2004 i686 i686 i386 GNU/Linux
 * $ gcc --version
 * gcc (GCC) 3.3.3 20040412 (Red Hat Linux 3.3.3-7)
 * Copyright (C) 2003 Free Software Foundation, Inc.
 * This is free software; see the source for copying conditions.  There is NO
 * warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
 * 
 * $ make vcp
 * g++     vcp.cc   -o vcp
 * $ ./vcp
 * ab
 * 1
 * $ 
 */