i(k1 OP k2) ROUND 2 (ko)

The definitive solution:

  i(v1 OP v2 OP ... OP vN)

after the optimization

  i(v1) OP i(v2) .. i(vN)

For example:

  i(gkd * .5 + gke)

after the opt becomes

  i(gkd) * .5 + i(gke)

It's simple and I think that it's the way. I try to write the fix.
If there are objections, I annul the ko and grant the defeat to
the points.

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