I guess that clears up the question, then (:-))
Thanks for checking!

	-- Pete--

On Tue, Jan 18, 2022 at 09:57:48PM +0100, joachim heintz wrote:
> well just by trial ...
> 
> instr Test
>  indx = 1
>  while indx < 10000000 do
>   iRnd = rnd:i(1)
>   if iRnd > .999999 then
>    printf_i "rnd(1) = %f in cycle %d.\n", indx, iRnd, indx
>   endif
>  indx += 1
>  od
> endin
> schedule("Test",0,0)
> 
> ... i get this:
> 
> rnd(1) = 0.999999 in cycle 4820758.
> rnd(1) = 1.000000 in cycle 6319223.
> rnd(1) = 0.999999 in cycle 7789384.
> rnd(1) = 1.000000 in cycle 9287849.
> 
> in other words: it takes some time, but it is not impossible.
> 
> 	j
> 
> 
> 
> 
> On 18/01/2022 20:37, Pete Goodeve wrote:
> >On Tue, Jan 18, 2022 at 07:44:22PM +0900, Tetsuya Miwa wrote:
> >>Hi all,
> >>
> >>I thought all the random number generators having range parameter in 
> >>Csound return the number in closed range (a <= N <= b, [a,b]).
> >>However, I started to feel less confident about it after checking the 
> >>manual.
> >>For example, the manual says rnd(x) returns a random number in the 
> >>unipolar range 0 to x.
> >>Is it [0,x] or [0,x) (semi-open)?
> >>
> >Not sure of your notation there, and one of the developers will have
> >to give the definitive answer, but as far as I know 'rnd(10)'  can include
> >the exact output '10', not just "arbitrarily close, but never exactly...".
> >
> >However, ift is really random, it might be hard to tell!
> >
> >	-- Pete --
> >
> >Csound mailing list
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> >Discussions of bugs and features can be posted here
> 
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